Base | Representation |
---|---|
bin | 1100110000111010001110… |
… | …0011000000101110100001 |
3 | 1211200200020121101122200221 |
4 | 3030032203203000232201 |
5 | 3314414423404122012 |
6 | 45503152033443041 |
7 | 2645644364610523 |
oct | 314164343005641 |
9 | 54620217348627 |
10 | 14034402020257 |
11 | 4520a58078693 |
12 | 16a7b64a10481 |
13 | 7aa591308758 |
14 | 3673a9399a13 |
15 | 19510120e507 |
hex | cc3a38c0ba1 |
14034402020257 has 2 divisors, whose sum is σ = 14034402020258. Its totient is φ = 14034402020256.
The previous prime is 14034402020231. The next prime is 14034402020273. The reversal of 14034402020257 is 75202020443041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12277462374241 + 1756939646016 = 3503921^2 + 1325496^2 .
It is a cyclic number.
It is not a de Polignac number, because 14034402020257 - 27 = 14034402020129 is a prime.
It is not a weakly prime, because it can be changed into another prime (14034402020057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7017201010128 + 7017201010129.
It is an arithmetic number, because the mean of its divisors is an integer number (7017201010129).
Almost surely, 214034402020257 is an apocalyptic number.
It is an amenable number.
14034402020257 is a deficient number, since it is larger than the sum of its proper divisors (1).
14034402020257 is an equidigital number, since it uses as much as digits as its factorization.
14034402020257 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 53760, while the sum is 34.
Adding to 14034402020257 its reverse (75202020443041), we get a palindrome (89236422463298).
The spelling of 14034402020257 in words is "fourteen trillion, thirty-four billion, four hundred two million, twenty thousand, two hundred fifty-seven".
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