Base | Representation |
---|---|
bin | 11111111010011000010001… |
… | …011010110001110110010011 |
3 | 200101221110001210002121202222 |
4 | 133322120101122301312103 |
5 | 121344003311241000113 |
6 | 1214300244440331255 |
7 | 41364020256036335 |
oct | 3772302132616623 |
9 | 611843053077688 |
10 | 140351233531283 |
11 | 407a1695419935 |
12 | 138a9014173b2b |
13 | 60410aba13898 |
14 | 26930708db455 |
15 | 1135cce9a0e08 |
hex | 7fa6116b1d93 |
140351233531283 has 2 divisors, whose sum is σ = 140351233531284. Its totient is φ = 140351233531282.
The previous prime is 140351233531219. The next prime is 140351233531309. The reversal of 140351233531283 is 382135332153041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140351233531283 - 26 = 140351233531219 is a prime.
It is a super-2 number, since 2×1403512335312832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (140351233534283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70175616765641 + 70175616765642.
It is an arithmetic number, because the mean of its divisors is an integer number (70175616765642).
Almost surely, 2140351233531283 is an apocalyptic number.
140351233531283 is a deficient number, since it is larger than the sum of its proper divisors (1).
140351233531283 is an equidigital number, since it uses as much as digits as its factorization.
140351233531283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 777600, while the sum is 44.
The spelling of 140351233531283 in words is "one hundred forty trillion, three hundred fifty-one billion, two hundred thirty-three million, five hundred thirty-one thousand, two hundred eighty-three".
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