140351233540041 has 6 divisors (see below), whose sum is σ = 202729559557850. Its totient is φ = 93567489026688.

The previous prime is 140351233540027. The next prime is 140351233540051. The reversal of 140351233540041 is 140045332153041.

140351233540041 is a `hidden beast` number, since 1 + 4 + 0 + 3 + 51 + 23 + 3 + 540 + 0 + 41 = 666.

It can be written as a sum of positive squares in only one way, i.e., 140327810768016 + 23422772025 = 11846004^2 + 153045^2 .

It is not a de Polignac number, because 140351233540041 - 2⁶ = 140351233539977 is a prime.

It is a super-2 number, since 2×140351233540041² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 140351233539978 and 140351233540005.

It is not an unprimeable number, because it can be changed into a prime (140351233540051) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 7797290752216 + ... + 7797290752233.

Almost surely, 2^{140351233540041} is an apocalyptic number.

It is an amenable number.

140351233540041 is a deficient number, since it is larger than the sum of its proper divisors (62378326017809).

140351233540041 is a wasteful number, since it uses less digits than its factorization.

140351233540041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15594581504455 (or 15594581504452 counting only the distinct ones).

The product of its (nonzero) digits is 86400, while the sum is 36.

Adding to 140351233540041 its reverse (140045332153041), we get a palindrome (280396565693082).

The spelling of 140351233540041 in words is "one hundred forty trillion, three hundred fifty-one billion, two hundred thirty-three million, five hundred forty thousand, forty-one".