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14035133524342 = 274124451452133
BaseRepresentation
bin1100110000111100111100…
…1001011110100101110110
31211200202010120211220122211
43030033033021132211312
53314422423140234332
645503352404244034
72646001456363510
oct314171711364566
954622116756584
1014035133524342
1145212a2a85517
1216a81299a061a
137aa679a285c8
143674385b4bb0
15195145556447
hexcc3cf25e976

14035133524342 has 16 divisors (see below), whose sum is σ = 24647063751072. Its totient is φ = 5868348511680.

The previous prime is 14035133524319. The next prime is 14035133524361. The reversal of 14035133524342 is 24342533153041.

It is a super-2 number, since 2×140351335243422 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14035133524295 and 14035133524304.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12225725493 + ... + 12225726640.

It is an arithmetic number, because the mean of its divisors is an integer number (1540441484442).

Almost surely, 214035133524342 is an apocalyptic number.

14035133524342 is a deficient number, since it is larger than the sum of its proper divisors (10611930226730).

14035133524342 is a wasteful number, since it uses less digits than its factorization.

14035133524342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24451452183.

The product of its (nonzero) digits is 518400, while the sum is 40.

Adding to 14035133524342 its reverse (24342533153041), we get a palindrome (38377666677383).

The spelling of 14035133524342 in words is "fourteen trillion, thirty-five billion, one hundred thirty-three million, five hundred twenty-four thousand, three hundred forty-two".

Divisors: 1 2 7 14 41 82 287 574 24451452133 48902904266 171160164931 342320329862 1002509537453 2005019074906 7017566762171 14035133524342