140352215134513 has 4 divisors (see below), whose sum is σ = 140461099709220. Its totient is φ = 140243330559808.

The previous prime is 140352215134499. The next prime is 140352215134519. The reversal of 140352215134513 is 315431512253041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 97672740234304 + 42679474900209 = 9882952^2 + 6532953^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140352215134513 is a prime.

It is a super-3 number, since 3×140352215134513³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140352215134519) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54442285420 + ... + 54442287997.

It is an arithmetic number, because the mean of its divisors is an integer number (35115274927305).

Almost surely, 2^{140352215134513} is an apocalyptic number.

It is an amenable number.

140352215134513 is a deficient number, since it is larger than the sum of its proper divisors (108884574707).

140352215134513 is a wasteful number, since it uses less digits than its factorization.

140352215134513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 108884574706.

The product of its (nonzero) digits is 216000, while the sum is 40.

Adding to 140352215134513 its reverse (315431512253041), we get a palindrome (455783727387554).

The spelling of 140352215134513 in words is "one hundred forty trillion, three hundred fifty-two billion, two hundred fifteen million, one hundred thirty-four thousand, five hundred thirteen".