Base | Representation |
---|---|
bin | 1000001010111001101… |
… | …0100100000110000011 |
3 | 111102022021210120000011 |
4 | 2002232122210012003 |
5 | 4244431434341033 |
6 | 144252144205351 |
7 | 13066244053162 |
oct | 2025632440603 |
9 | 442267716004 |
10 | 140365152643 |
11 | 5458a518791 |
12 | 23254009857 |
13 | 1030c422151 |
14 | 6b17d213d9 |
15 | 39b7ceeccd |
hex | 20ae6a4183 |
140365152643 has 2 divisors, whose sum is σ = 140365152644. Its totient is φ = 140365152642.
The previous prime is 140365152553. The next prime is 140365152649. The reversal of 140365152643 is 346251563041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140365152643 - 217 = 140365021571 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 140365152596 and 140365152605.
It is not a weakly prime, because it can be changed into another prime (140365152649) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70182576321 + 70182576322.
It is an arithmetic number, because the mean of its divisors is an integer number (70182576322).
Almost surely, 2140365152643 is an apocalyptic number.
140365152643 is a deficient number, since it is larger than the sum of its proper divisors (1).
140365152643 is an equidigital number, since it uses as much as digits as its factorization.
140365152643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 259200, while the sum is 40.
The spelling of 140365152643 in words is "one hundred forty billion, three hundred sixty-five million, one hundred fifty-two thousand, six hundred forty-three".
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