Search a number
-
+
140365900057 is a prime number
BaseRepresentation
bin1000001010111001110…
…1011010100100011001
3111102022100012112021011
42002232131122210121
54244432132300212
6144252212213521
713066253315215
oct2025635324431
9442270175234
10140365900057
115458a989289
122325430a2a1
131030c6243c6
146b18077945
1539b7deb4a7
hex20ae75a919

140365900057 has 2 divisors, whose sum is σ = 140365900058. Its totient is φ = 140365900056.

The previous prime is 140365900043. The next prime is 140365900061. The reversal of 140365900057 is 750009563041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110040812176 + 30325087881 = 331724^2 + 174141^2 .

It is an emirp because it is prime and its reverse (750009563041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140365900057 - 215 = 140365867289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140365899992 and 140365900019.

It is not a weakly prime, because it can be changed into another prime (140365904057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70182950028 + 70182950029.

It is an arithmetic number, because the mean of its divisors is an integer number (70182950029).

Almost surely, 2140365900057 is an apocalyptic number.

It is an amenable number.

140365900057 is a deficient number, since it is larger than the sum of its proper divisors (1).

140365900057 is an equidigital number, since it uses as much as digits as its factorization.

140365900057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 113400, while the sum is 40.

The spelling of 140365900057 in words is "one hundred forty billion, three hundred sixty-five million, nine hundred thousand, fifty-seven".