14040334113 has 16 divisors (see below), whose sum is σ = 20314383936. Its totient is φ = 8574246720.

The previous prime is 14040334081. The next prime is 14040334123. The reversal of 14040334113 is 31143304041.

It is not a de Polignac number, because 14040334113 - 2⁵ = 14040334081 is a prime.

It is a super-3 number, since 3×14040334113³ (a number of 31 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (14040334123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1368970 + ... + 1379187.

It is an arithmetic number, because the mean of its divisors is an integer number (1269648996).

Almost surely, 2^14040334113 is an apocalyptic number.

14040334113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

14040334113 is a deficient number, since it is larger than the sum of its proper divisors (6274049823).

14040334113 is a wasteful number, since it uses less digits than its factorization.

14040334113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2748304.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 14040334113 its reverse (31143304041), we get a palindrome (45183638154).

The spelling of 14040334113 in words is "fourteen billion, forty million, three hundred thirty-four thousand, one hundred thirteen".