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140404144210307 is a prime number
BaseRepresentation
bin11111111011001001100011…
…001001000000000110000011
3200102010111122012212121101122
4133323021203021000012003
5121400340141404212212
61214340435020022455
741400602403300635
oct3773114311000603
9612114565777348
10140404144210307
114081207709513a
12138b731b991a2b
1360460917c2c93
14269584da22a55
151137379b44272
hex7fb263240183

140404144210307 has 2 divisors, whose sum is σ = 140404144210308. Its totient is φ = 140404144210306.

The previous prime is 140404144210303. The next prime is 140404144210391. The reversal of 140404144210307 is 703012441404041.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 140404144210307 - 22 = 140404144210303 is a prime.

It is a super-2 number, since 2×1404041442103072 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (140404144210303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70202072105153 + 70202072105154.

It is an arithmetic number, because the mean of its divisors is an integer number (70202072105154).

Almost surely, 2140404144210307 is an apocalyptic number.

140404144210307 is a deficient number, since it is larger than the sum of its proper divisors (1).

140404144210307 is an equidigital number, since it uses as much as digits as its factorization.

140404144210307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43008, while the sum is 35.

Adding to 140404144210307 its reverse (703012441404041), we get a palindrome (843416585614348).

The spelling of 140404144210307 in words is "one hundred forty trillion, four hundred four billion, one hundred forty-four million, two hundred ten thousand, three hundred seven".