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14040434121 = 373132136077
BaseRepresentation
bin11010001001110000…
…00000010111001001
31100020111112221202120
431010320000113021
5212223322342441
610241115121453
71004635502160
oct150470002711
940214487676
1014040434121
115a55505a6a
12287a143289
131429ac81ac
14972a003d7
1557296d966
hex344e005c9

14040434121 has 16 divisors (see below), whose sum is σ = 21463311744. Its totient is φ = 7997468544.

The previous prime is 14040434119. The next prime is 14040434171. The reversal of 14040434121 is 12143404041.

It is not a de Polignac number, because 14040434121 - 21 = 14040434119 is a prime.

It is a super-2 number, since 2×140404341212 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14040434091 and 14040434100.

It is not an unprimeable number, because it can be changed into a prime (14040434101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1061466 + ... + 1074611.

It is an arithmetic number, because the mean of its divisors is an integer number (1341456984).

Almost surely, 214040434121 is an apocalyptic number.

It is an amenable number.

14040434121 is a deficient number, since it is larger than the sum of its proper divisors (7422877623).

14040434121 is a wasteful number, since it uses less digits than its factorization.

14040434121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2136400.

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 14040434121 its reverse (12143404041), we get a palindrome (26183838162).

The spelling of 14040434121 in words is "fourteen billion, forty million, four hundred thirty-four thousand, one hundred twenty-one".

Divisors: 1 3 7 21 313 939 2191 6573 2136077 6408231 14952539 44857617 668592101 2005776303 4680144707 14040434121