140405052234001 has 4 divisors (see below), whose sum is σ = 140405099295600. Its totient is φ = 140405005172404.

The previous prime is 140405052233989. The next prime is 140405052234011. The reversal of 140405052234001 is 100432250504041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140405052234001 - 2¹⁵ = 140405052201233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140405052234011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18729031 + ... + 25131388.

It is an arithmetic number, because the mean of its divisors is an integer number (35101274823900).

Almost surely, 2^{140405052234001} is an apocalyptic number.

It is an amenable number.

140405052234001 is a deficient number, since it is larger than the sum of its proper divisors (47061599).

140405052234001 is an equidigital number, since it uses as much as digits as its factorization.

140405052234001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47061598.

The product of its (nonzero) digits is 19200, while the sum is 31.

The spelling of 140405052234001 in words is "one hundred forty trillion, four hundred five billion, fifty-two million, two hundred thirty-four thousand, one".