Base | Representation |
---|---|
bin | 1100110001010010111101… |
… | …1101011111010010100010 |
3 | 1211201022101112002222021212 |
4 | 3030110233131133102202 |
5 | 3320022024323200424 |
6 | 45510211113550122 |
7 | 2646301111515635 |
oct | 314245735372242 |
9 | 54638345088255 |
10 | 14041044350114 |
11 | 45238565393a1 |
12 | 16a92b9415342 |
13 | 7ab0ac4a1252 |
14 | 36783960dc1c |
15 | 19538e42710e |
hex | cc52f75f4a2 |
14041044350114 has 4 divisors (see below), whose sum is σ = 21061566525174. Its totient is φ = 7020522175056.
The previous prime is 14041044350101. The next prime is 14041044350119. The reversal of 14041044350114 is 41105344014041.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13949739454225 + 91304895889 = 3734935^2 + 302167^2 .
It is a super-2 number, since 2×140410443501142 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (14041044350119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3510261087527 + ... + 3510261087530.
Almost surely, 214041044350114 is an apocalyptic number.
14041044350114 is a deficient number, since it is larger than the sum of its proper divisors (7020522175060).
14041044350114 is an equidigital number, since it uses as much as digits as its factorization.
14041044350114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7020522175059.
The product of its (nonzero) digits is 15360, while the sum is 32.
Adding to 14041044350114 its reverse (41105344014041), we get a palindrome (55146388364155).
The spelling of 14041044350114 in words is "fourteen trillion, forty-one billion, forty-four million, three hundred fifty thousand, one hundred fourteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.118 sec. • engine limits •