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14041044350114 = 27020522175057
BaseRepresentation
bin1100110001010010111101…
…1101011111010010100010
31211201022101112002222021212
43030110233131133102202
53320022024323200424
645510211113550122
72646301111515635
oct314245735372242
954638345088255
1014041044350114
1145238565393a1
1216a92b9415342
137ab0ac4a1252
1436783960dc1c
1519538e42710e
hexcc52f75f4a2

14041044350114 has 4 divisors (see below), whose sum is σ = 21061566525174. Its totient is φ = 7020522175056.

The previous prime is 14041044350101. The next prime is 14041044350119. The reversal of 14041044350114 is 41105344014041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 13949739454225 + 91304895889 = 3734935^2 + 302167^2 .

It is a super-2 number, since 2×140410443501142 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14041044350119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3510261087527 + ... + 3510261087530.

Almost surely, 214041044350114 is an apocalyptic number.

14041044350114 is a deficient number, since it is larger than the sum of its proper divisors (7020522175060).

14041044350114 is an equidigital number, since it uses as much as digits as its factorization.

14041044350114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7020522175059.

The product of its (nonzero) digits is 15360, while the sum is 32.

Adding to 14041044350114 its reverse (41105344014041), we get a palindrome (55146388364155).

The spelling of 14041044350114 in words is "fourteen trillion, forty-one billion, forty-four million, three hundred fifty thousand, one hundred fourteen".

Divisors: 1 2 7020522175057 14041044350114