14041113 has 4 divisors (see below), whose sum is σ = 18721488. Its totient is φ = 9360740.

The previous prime is 14041103. The next prime is 14041117. The reversal of 14041113 is 31114041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14041113 - 2⁵ = 14041081 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14041092 and 14041101.

It is not an unprimeable number, because it can be changed into a prime (14041117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2340183 + ... + 2340188.

It is an arithmetic number, because the mean of its divisors is an integer number (4680372).

Almost surely, 2^14041113 is an apocalyptic number.

It is an amenable number.

14041113 is a deficient number, since it is larger than the sum of its proper divisors (4680375).

14041113 is an equidigital number, since it uses as much as digits as its factorization.

14041113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4680374.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 14041113 is about 3747.1473149584. The cubic root of 14041113 is about 241.2499200873.

Adding to 14041113 its reverse (31114041), we get a palindrome (45155154).

The spelling of 14041113 in words is "fourteen million, forty-one thousand, one hundred thirteen".