140411204035051 has 4 divisors (see below), whose sum is σ = 140411426409504. Its totient is φ = 140410981660600.

The previous prime is 140411204035031. The next prime is 140411204035079. The reversal of 140411204035051 is 150530402114041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140411204035051 - 2¹³ = 140411204026859 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140411204035031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110237395 + ... + 111503836.

It is an arithmetic number, because the mean of its divisors is an integer number (35102856602376).

Almost surely, 2^{140411204035051} is an apocalyptic number.

140411204035051 is a deficient number, since it is larger than the sum of its proper divisors (222374453).

140411204035051 is an equidigital number, since it uses as much as digits as its factorization.

140411204035051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 222374452.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 140411204035051 its reverse (150530402114041), we get a palindrome (290941606149092).

The spelling of 140411204035051 in words is "one hundred forty trillion, four hundred eleven billion, two hundred four million, thirty-five thousand, fifty-one".