Base | Representation |
---|---|
bin | 1100110001010011010011… |
… | …0000001111110010011001 |
3 | 1211201022121201012122112200 |
4 | 3030110310300033302121 |
5 | 3320022220041402213 |
6 | 45510224005200413 |
7 | 2646303240365511 |
oct | 314246460176231 |
9 | 54638551178480 |
10 | 14041133153433 |
11 | 45238a1682671 |
12 | 16a9323100109 |
13 | 7ab0c49c45a9 |
14 | 367847328841 |
15 | 195397119273 |
hex | cc534c0fc99 |
14041133153433 has 24 divisors (see below), whose sum is σ = 20939703732480. Its totient is φ = 9057142435680.
The previous prime is 14041133153413. The next prime is 14041133153461. The reversal of 14041133153433 is 33435133114041.
14041133153433 is a `hidden beast` number, since 1 + 4 + 0 + 4 + 113 + 3 + 1 + 534 + 3 + 3 = 666.
It is not a de Polignac number, because 14041133153433 - 25 = 14041133153401 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14041133153413) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3059578 + ... + 6119091.
It is an arithmetic number, because the mean of its divisors is an integer number (872487655520).
Almost surely, 214041133153433 is an apocalyptic number.
It is an amenable number.
14041133153433 is a deficient number, since it is larger than the sum of its proper divisors (6898570579047).
14041133153433 is a wasteful number, since it uses less digits than its factorization.
14041133153433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9184189 (or 9184186 counting only the distinct ones).
The product of its (nonzero) digits is 77760, while the sum is 36.
Adding to 14041133153433 its reverse (33435133114041), we get a palindrome (47476266267474).
The spelling of 14041133153433 in words is "fourteen trillion, forty-one billion, one hundred thirty-three million, one hundred fifty-three thousand, four hundred thirty-three".
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