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14041255433 = 223313201167
BaseRepresentation
bin11010001001110110…
…01000111000001001
31100020120002200101112
431010323020320021
5212224030133213
610241144500105
71004645462522
oct150473107011
940216080345
1014041255433
115a55a17037
12287a47a635
13142a024c8a
14972b75849
15572a81ea8
hex344ec8e09

14041255433 has 8 divisors (see below), whose sum is σ = 14149352448. Its totient is φ = 13933561824.

The previous prime is 14041255427. The next prime is 14041255453. The reversal of 14041255433 is 33455214041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14041255433 - 218 = 14040993289 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 14041255433.

It is not an unprimeable number, because it can be changed into a prime (14041255453) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30785 + ... + 170382.

It is an arithmetic number, because the mean of its divisors is an integer number (1768669056).

Almost surely, 214041255433 is an apocalyptic number.

It is an amenable number.

14041255433 is a deficient number, since it is larger than the sum of its proper divisors (108097015).

14041255433 is a wasteful number, since it uses less digits than its factorization.

14041255433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 201703.

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 14041255433 its reverse (33455214041), we get a palindrome (47496469474).

The spelling of 14041255433 in words is "fourteen billion, forty-one million, two hundred fifty-five thousand, four hundred thirty-three".

Divisors: 1 223 313 69799 201167 44860241 62965271 14041255433