14042012003433 has 24 divisors (see below), whose sum is σ = 21382665747456. Its totient is φ = 8866610179200.

The previous prime is 14042012003431. The next prime is 14042012003489. The reversal of 14042012003433 is 33430021024041.

14042012003433 is a `hidden beast` number, since 1 + 4 + 0 + 4 + 20 + 1 + 200 + 3 + 433 = 666.

It is not a de Polignac number, because 14042012003433 - 2¹ = 14042012003431 is a prime.

It is a super-2 number, since 2×14042012003433² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14042012003397 and 14042012003406.

It is not an unprimeable number, because it can be changed into a prime (14042012003431) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 535410208 + ... + 535436433.

It is an arithmetic number, because the mean of its divisors is an integer number (890944406144).

Almost surely, 2^{14042012003433} is an apocalyptic number.

It is an amenable number.

14042012003433 is a deficient number, since it is larger than the sum of its proper divisors (7340653744023).

14042012003433 is a wasteful number, since it uses less digits than its factorization.

14042012003433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1070846725 (or 1070846722 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 14042012003433 its reverse (33430021024041), we get a palindrome (47472033027474).

The spelling of 14042012003433 in words is "fourteen trillion, forty-two billion, twelve million, three thousand, four hundred thirty-three".