14042040140113 has 4 divisors (see below), whose sum is σ = 14042049397360. Its totient is φ = 14042030882868.

The previous prime is 14042040140099. The next prime is 14042040140129. The reversal of 14042040140113 is 31104104024041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14042040140113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14042040140173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1761195 + ... + 5584432.

It is an arithmetic number, because the mean of its divisors is an integer number (3510512349340).

Almost surely, 2^{14042040140113} is an apocalyptic number.

It is an amenable number.

14042040140113 is a deficient number, since it is larger than the sum of its proper divisors (9257247).

14042040140113 is an equidigital number, since it uses as much as digits as its factorization.

14042040140113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9257246.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 14042040140113 its reverse (31104104024041), we get a palindrome (45146144164154).

The spelling of 14042040140113 in words is "fourteen trillion, forty-two billion, forty million, one hundred forty thousand, one hundred thirteen".