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140420511433 is a prime number
BaseRepresentation
bin1000001011000110110…
…1101111011011001001
3111102110010222001222201
42002301231233123021
54300040122331213
6144301442520201
713100515440106
oct2026155573311
9442403861881
10140420511433
1154608799654
122326a666061
131031aa35727
146b21411aad
1539bcad76dd
hex20b1b6f6c9

140420511433 has 2 divisors, whose sum is σ = 140420511434. Its totient is φ = 140420511432.

The previous prime is 140420511419. The next prime is 140420511437. The reversal of 140420511433 is 334115024041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75419989129 + 65000522304 = 274627^2 + 254952^2 .

It is a cyclic number.

It is not a de Polignac number, because 140420511433 - 213 = 140420503241 is a prime.

It is a super-2 number, since 2×1404205114332 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (140420511437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70210255716 + 70210255717.

It is an arithmetic number, because the mean of its divisors is an integer number (70210255717).

Almost surely, 2140420511433 is an apocalyptic number.

It is an amenable number.

140420511433 is a deficient number, since it is larger than the sum of its proper divisors (1).

140420511433 is an equidigital number, since it uses as much as digits as its factorization.

140420511433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 140420511433 its reverse (334115024041), we get a palindrome (474535535474).

The spelling of 140420511433 in words is "one hundred forty billion, four hundred twenty million, five hundred eleven thousand, four hundred thirty-three".