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140421302424257 is a prime number
BaseRepresentation
bin11111111011011001100001…
…110110011001001011000001
3200102012010221000002012001012
4133323121201312121023001
5121401130311410034012
61214352353352050305
741402050530562211
oct3773314166311301
9612163830065035
10140421302424257
1140819381496248
12138ba70a093995
1360478974ccbba
1426965da728241
151137a3116e622
hex7fb661d992c1

140421302424257 has 2 divisors, whose sum is σ = 140421302424258. Its totient is φ = 140421302424256.

The previous prime is 140421302424223. The next prime is 140421302424397. The reversal of 140421302424257 is 752424203124041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81570448836496 + 58850853587761 = 9031636^2 + 7671431^2 .

It is a cyclic number.

It is not a de Polignac number, because 140421302424257 - 232 = 140417007456961 is a prime.

It is not a weakly prime, because it can be changed into another prime (140421302424217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70210651212128 + 70210651212129.

It is an arithmetic number, because the mean of its divisors is an integer number (70210651212129).

Almost surely, 2140421302424257 is an apocalyptic number.

It is an amenable number.

140421302424257 is a deficient number, since it is larger than the sum of its proper divisors (1).

140421302424257 is an equidigital number, since it uses as much as digits as its factorization.

140421302424257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 430080, while the sum is 41.

Adding to 140421302424257 its reverse (752424203124041), we get a palindrome (892845505548298).

The spelling of 140421302424257 in words is "one hundred forty trillion, four hundred twenty-one billion, three hundred two million, four hundred twenty-four thousand, two hundred fifty-seven".