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140424332234041 is a prime number
BaseRepresentation
bin11111111011011100010110…
…011100001100110100111001
3200102012102202011012110201101
4133323130112130030310321
5121401203013022442131
61214354014143251401
741402215600541662
oct3773342634146471
9612172664173641
10140424332234041
114081a696767179
12138bb2148a9b61
136047c5b12095b
142696806c90369
151137b5c150c61
hex7fb71670cd39

140424332234041 has 2 divisors, whose sum is σ = 140424332234042. Its totient is φ = 140424332234040.

The previous prime is 140424332234029. The next prime is 140424332234077. The reversal of 140424332234041 is 140432233424041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 84260998825641 + 56163333408400 = 9179379^2 + 7494220^2 .

It is a cyclic number.

It is not a de Polignac number, because 140424332234041 - 211 = 140424332231993 is a prime.

It is a super-3 number, since 3×1404243322340413 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (140424332234341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70212166117020 + 70212166117021.

It is an arithmetic number, because the mean of its divisors is an integer number (70212166117021).

Almost surely, 2140424332234041 is an apocalyptic number.

It is an amenable number.

140424332234041 is a deficient number, since it is larger than the sum of its proper divisors (1).

140424332234041 is an equidigital number, since it uses as much as digits as its factorization.

140424332234041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 221184, while the sum is 37.

Adding to 140424332234041 its reverse (140432233424041), we get a palindrome (280856565658082).

The spelling of 140424332234041 in words is "one hundred forty trillion, four hundred twenty-four billion, three hundred thirty-two million, two hundred thirty-four thousand, forty-one".