Base | Representation |
---|---|
bin | 11111111011011101001011… |
… | …000001000011111110011001 |
3 | 200102012112000121222200200012 |
4 | 133323131023001003332121 |
5 | 121401211314330443340 |
6 | 1214354241453251305 |
7 | 41402246501225564 |
oct | 3773351301037631 |
9 | 612175017880605 |
10 | 140425214312345 |
11 | 4081aaa9668706 |
12 | 138bb420193b35 |
13 | 604806bab0b91 |
14 | 269688c0a34db |
15 | 1137bae7dc565 |
hex | 7fb74b043f99 |
140425214312345 has 48 divisors (see below), whose sum is σ = 172526924361792. Its totient is φ = 109693872241920.
The previous prime is 140425214312329. The next prime is 140425214312353. The reversal of 140425214312345 is 543213412524041.
It is not a de Polignac number, because 140425214312345 - 24 = 140425214312329 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6245828474 + ... + 6245850956.
It is an arithmetic number, because the mean of its divisors is an integer number (3594310924204).
Almost surely, 2140425214312345 is an apocalyptic number.
It is an amenable number.
140425214312345 is a deficient number, since it is larger than the sum of its proper divisors (32101710049447).
140425214312345 is an equidigital number, since it uses as much as digits as its factorization.
140425214312345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23370 (or 23101 counting only the distinct ones).
The product of its (nonzero) digits is 460800, while the sum is 41.
Adding to 140425214312345 its reverse (543213412524041), we get a palindrome (683638626836386).
The spelling of 140425214312345 in words is "one hundred forty trillion, four hundred twenty-five billion, two hundred fourteen million, three hundred twelve thousand, three hundred forty-five".
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