Base | Representation |
---|---|
bin | 1100110001011011000000… |
… | …0100010100010011110010 |
3 | 1211201111221220010120111221 |
4 | 3030112300010110103302 |
5 | 3320040434203344102 |
6 | 45511205152055254 |
7 | 2646405431402353 |
oct | 314266004242362 |
9 | 54644856116457 |
10 | 14043202012402 |
11 | 4524763480a72 |
12 | 16a97bbb3452a |
13 | 7ab3644cacb4 |
14 | 3679a1dc9d2a |
15 | 195468a7e637 |
hex | cc5b01144f2 |
14043202012402 has 8 divisors (see below), whose sum is σ = 21068529340716. Its totient is φ = 7020358898832.
The previous prime is 14043202012393. The next prime is 14043202012409. The reversal of 14043202012402 is 20421020234041.
It can be written as a sum of positive squares in 2 ways, for example, as 13835119154481 + 208082857921 = 3719559^2 + 456161^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×140432020124023 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (14043202012409) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 621039553 + ... + 621062164.
Almost surely, 214043202012402 is an apocalyptic number.
14043202012402 is a deficient number, since it is larger than the sum of its proper divisors (7025327328314).
14043202012402 is a wasteful number, since it uses less digits than its factorization.
14043202012402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1242107372.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 14043202012402 its reverse (20421020234041), we get a palindrome (34464222246443).
The spelling of 14043202012402 in words is "fourteen trillion, forty-three billion, two hundred two million, twelve thousand, four hundred two".
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