14043310025441 has 2 divisors, whose sum is σ = 14043310025442. Its totient is φ = 14043310025440.

The previous prime is 14043310025399. The next prime is 14043310025461. The reversal of 14043310025441 is 14452001334041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13416133142416 + 627176883025 = 3662804^2 + 791945^2 .

It is a cyclic number.

It is not a de Polignac number, because 14043310025441 - 2³⁴ = 14026130156257 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14043310025398 and 14043310025407.

It is not a weakly prime, because it can be changed into another prime (14043310025461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7021655012720 + 7021655012721.

It is an arithmetic number, because the mean of its divisors is an integer number (7021655012721).

Almost surely, 2^{14043310025441} is an apocalyptic number.

It is an amenable number.

14043310025441 is a deficient number, since it is larger than the sum of its proper divisors (1).

14043310025441 is an equidigital number, since it uses as much as digits as its factorization.

14043310025441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 14043310025441 its reverse (14452001334041), we get a palindrome (28495311359482).

The spelling of 14043310025441 in words is "fourteen trillion, forty-three billion, three hundred ten million, twenty-five thousand, four hundred forty-one".