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14043335402346 = 2323101763300017
BaseRepresentation
bin1100110001011011100000…
…0001001010001101101010
31211201112022012010111010020
43030112320001022031222
53320041222330333341
645511230315101310
72646411641242335
oct314267001121552
954645265114106
1014043335402346
1145248217a8898
1216a9838741836
137ab386032763
143679b59cd61c
1519547562c566
hexcc5b804a36a

14043335402346 has 16 divisors (see below), whose sum is σ = 29307830405184. Its totient is φ = 4477585200704.

The previous prime is 14043335402321. The next prime is 14043335402381. The reversal of 14043335402346 is 64320453334041.

It is a junction number, because it is equal to n+sod(n) for n = 14043335402298 and 14043335402307.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50881649871 + ... + 50881650146.

It is an arithmetic number, because the mean of its divisors is an integer number (1831739400324).

Almost surely, 214043335402346 is an apocalyptic number.

14043335402346 is an abundant number, since it is smaller than the sum of its proper divisors (15264495002838).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14043335402346 is a wasteful number, since it uses less digits than its factorization.

14043335402346 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101763300045.

The product of its (nonzero) digits is 1244160, while the sum is 42.

Adding to 14043335402346 its reverse (64320453334041), we get a palindrome (78363788736387).

The spelling of 14043335402346 in words is "fourteen trillion, forty-three billion, three hundred thirty-five million, four hundred two thousand, three hundred forty-six".

Divisors: 1 2 3 6 23 46 69 138 101763300017 203526600034 305289900051 610579800102 2340555900391 4681111800782 7021667701173 14043335402346