Base | Representation |
---|---|
bin | 1100110001011110001110… |
… | …0100010000000000111001 |
3 | 1211201121012002220210002102 |
4 | 3030113203210100000321 |
5 | 3320044221400141213 |
6 | 45511431014513145 |
7 | 2646436022351210 |
oct | 314274344200071 |
9 | 54647162823072 |
10 | 14044066021433 |
11 | 4525067160818 |
12 | 16a9a013657b5 |
13 | 7ab471502846 |
14 | 367a44a58077 |
15 | 1954b984c158 |
hex | cc5e3910039 |
14044066021433 has 4 divisors (see below), whose sum is σ = 16050361167360. Its totient is φ = 12037770875508.
The previous prime is 14044066021411. The next prime is 14044066021463. The reversal of 14044066021433 is 33412066044041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 14044066021433 - 26 = 14044066021369 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14044066021463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1003147572953 + ... + 1003147572966.
It is an arithmetic number, because the mean of its divisors is an integer number (4012590291840).
Almost surely, 214044066021433 is an apocalyptic number.
It is an amenable number.
14044066021433 is a deficient number, since it is larger than the sum of its proper divisors (2006295145927).
14044066021433 is an equidigital number, since it uses as much as digits as its factorization.
14044066021433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2006295145926.
The product of its (nonzero) digits is 165888, while the sum is 38.
The spelling of 14044066021433 in words is "fourteen trillion, forty-four billion, sixty-six million, twenty-one thousand, four hundred thirty-three".
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