Base | Representation |
---|---|
bin | 1000001011001100000… |
… | …0001011010001101001 |
3 | 111102111122121222011221 |
4 | 2002303000023101221 |
5 | 4300111140340241 |
6 | 144303534022041 |
7 | 13101200222515 |
oct | 2026300132151 |
9 | 442448558157 |
10 | 140442121321 |
11 | 54619a09467 |
12 | 23275947921 |
13 | 10322360848 |
14 | 6b24239145 |
15 | 39be9555d1 |
hex | 20b300b469 |
140442121321 has 2 divisors, whose sum is σ = 140442121322. Its totient is φ = 140442121320.
The previous prime is 140442121273. The next prime is 140442121367. The reversal of 140442121321 is 123121244041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 139923876096 + 518245225 = 374064^2 + 22765^2 .
It is a cyclic number.
It is not a de Polignac number, because 140442121321 - 213 = 140442113129 is a prime.
It is a super-2 number, since 2×1404421213212 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (140442125321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70221060660 + 70221060661.
It is an arithmetic number, because the mean of its divisors is an integer number (70221060661).
Almost surely, 2140442121321 is an apocalyptic number.
It is an amenable number.
140442121321 is a deficient number, since it is larger than the sum of its proper divisors (1).
140442121321 is an equidigital number, since it uses as much as digits as its factorization.
140442121321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 140442121321 its reverse (123121244041), we get a palindrome (263563365362).
The spelling of 140442121321 in words is "one hundred forty billion, four hundred forty-two million, one hundred twenty-one thousand, three hundred twenty-one".
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