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14044343224531 is a prime number
BaseRepresentation
bin1100110001011111010000…
…0101101100100011010011
31211201121220102112011020211
43030113310011230203103
53320100303331141111
645511514320144551
72646445626502414
oct314276405544323
954647812464224
1014044343224531
114525199684594
1216a9a7a168157
137ab4b6a7b149
14367a6d7b580b
151954d3d56521
hexcc5f416c8d3

14044343224531 has 2 divisors, whose sum is σ = 14044343224532. Its totient is φ = 14044343224530.

The previous prime is 14044343224519. The next prime is 14044343224573. The reversal of 14044343224531 is 13542234344041.

14044343224531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14044343224531 - 215 = 14044343191763 is a prime.

It is a super-2 number, since 2×140443432245312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14044343224501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7022171612265 + 7022171612266.

It is an arithmetic number, because the mean of its divisors is an integer number (7022171612266).

Almost surely, 214044343224531 is an apocalyptic number.

14044343224531 is a deficient number, since it is larger than the sum of its proper divisors (1).

14044343224531 is an equidigital number, since it uses as much as digits as its factorization.

14044343224531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 552960, while the sum is 40.

Adding to 14044343224531 its reverse (13542234344041), we get a palindrome (27586577568572).

The spelling of 14044343224531 in words is "fourteen trillion, forty-four billion, three hundred forty-three million, two hundred twenty-four thousand, five hundred thirty-one".