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140444113 is a prime number
BaseRepresentation
bin10000101111100…
…00000111010001
3100210021022002211
420113300013101
5241423202423
621534112121
73323520025
oct1027600721
9323238084
10140444113
1172305817
123b04b641
1323134534
141491c385
15c4e310d
hex85f01d1

140444113 has 2 divisors, whose sum is σ = 140444114. Its totient is φ = 140444112.

The previous prime is 140444107. The next prime is 140444137. The reversal of 140444113 is 311444041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 134722449 + 5721664 = 11607^2 + 2392^2 .

It is an emirp because it is prime and its reverse (311444041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140444113 is a prime.

It is not a weakly prime, because it can be changed into another prime (140444153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70222056 + 70222057.

It is an arithmetic number, because the mean of its divisors is an integer number (70222057).

Almost surely, 2140444113 is an apocalyptic number.

It is an amenable number.

140444113 is a deficient number, since it is larger than the sum of its proper divisors (1).

140444113 is an equidigital number, since it uses as much as digits as its factorization.

140444113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 22.

The square root of 140444113 is about 11850.9119058408. The cubic root of 140444113 is about 519.7978911309.

Adding to 140444113 its reverse (311444041), we get a palindrome (451888154).

The spelling of 140444113 in words is "one hundred forty million, four hundred forty-four thousand, one hundred thirteen".