Base | Representation |
---|---|
bin | 11010001010001110… |
… | …10101000010110001 |
3 | 1100020210010000212121 |
4 | 31011013111002301 |
5 | 212230334412433 |
6 | 10241341154241 |
7 | 1005014602156 |
oct | 150507250261 |
9 | 40223100777 |
10 | 14044450993 |
11 | 5a577a99a1 |
12 | 287b55b981 |
13 | 142a8a3641 |
14 | 97336822d |
15 | 572eb3c2d |
hex | 3451d50b1 |
14044450993 has 2 divisors, whose sum is σ = 14044450994. Its totient is φ = 14044450992.
The previous prime is 14044450949. The next prime is 14044451039. The reversal of 14044450993 is 39905444041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9652473009 + 4391977984 = 98247^2 + 66272^2 .
It is a cyclic number.
It is not a de Polignac number, because 14044450993 - 221 = 14042353841 is a prime.
It is not a weakly prime, because it can be changed into another prime (14044420993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7022225496 + 7022225497.
It is an arithmetic number, because the mean of its divisors is an integer number (7022225497).
Almost surely, 214044450993 is an apocalyptic number.
It is an amenable number.
14044450993 is a deficient number, since it is larger than the sum of its proper divisors (1).
14044450993 is an equidigital number, since it uses as much as digits as its factorization.
14044450993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 43.
The spelling of 14044450993 in words is "fourteen billion, forty-four million, four hundred fifty thousand, nine hundred ninety-three".
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