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140450110513 is a prime number
BaseRepresentation
bin1000001011001101111…
…0101001110000110001
3111102112012122212021221
42002303132221300301
54300120212014023
6144304421145041
713101325145566
oct2026336516061
9442465585257
10140450110513
11546234758a9
122327855b181
1310323bca08b
146b2531886d
1539c04d285d
hex20b37a9c31

140450110513 has 2 divisors, whose sum is σ = 140450110514. Its totient is φ = 140450110512.

The previous prime is 140450110483. The next prime is 140450110523. The reversal of 140450110513 is 315011054041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120953015089 + 19497095424 = 347783^2 + 139632^2 .

It is a cyclic number.

It is not a de Polignac number, because 140450110513 - 213 = 140450102321 is a prime.

It is a super-2 number, since 2×1404501105132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (140450110523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70225055256 + 70225055257.

It is an arithmetic number, because the mean of its divisors is an integer number (70225055257).

Almost surely, 2140450110513 is an apocalyptic number.

It is an amenable number.

140450110513 is a deficient number, since it is larger than the sum of its proper divisors (1).

140450110513 is an equidigital number, since it uses as much as digits as its factorization.

140450110513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 140450110513 its reverse (315011054041), we get a palindrome (455461164554).

The spelling of 140450110513 in words is "one hundred forty billion, four hundred fifty million, one hundred ten thousand, five hundred thirteen".