Base | Representation |
---|---|
bin | 110101100100… |
… | …111110111001 |
3 | 222102120021101 |
4 | 311210332321 |
5 | 12043420423 |
6 | 1221011401 |
7 | 230244565 |
oct | 65447671 |
9 | 28376241 |
10 | 14045113 |
11 | 7a23335 |
12 | 4853b61 |
13 | 2ba9b24 |
14 | 1c186a5 |
15 | 13767ad |
hex | d64fb9 |
14045113 has 2 divisors, whose sum is σ = 14045114. Its totient is φ = 14045112.
The previous prime is 14045107. The next prime is 14045131. The reversal of 14045113 is 31154041.
Together with next prime (14045131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12938409 + 1106704 = 3597^2 + 1052^2 .
It is an emirp because it is prime and its reverse (31154041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14045113 - 213 = 14036921 is a prime.
It is not a weakly prime, because it can be changed into another prime (14045153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7022556 + 7022557.
It is an arithmetic number, because the mean of its divisors is an integer number (7022557).
Almost surely, 214045113 is an apocalyptic number.
It is an amenable number.
14045113 is a deficient number, since it is larger than the sum of its proper divisors (1).
14045113 is an equidigital number, since it uses as much as digits as its factorization.
14045113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 19.
The square root of 14045113 is about 3747.6810163086. The cubic root of 14045113 is about 241.2728268198.
Adding to 14045113 its reverse (31154041), we get a palindrome (45199154).
The spelling of 14045113 in words is "fourteen million, forty-five thousand, one hundred thirteen".
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