Base | Representation |
---|---|
bin | 1100110001100100001010… |
… | …1101000000111011110011 |
3 | 1211201202022100022202000022 |
4 | 3030121002231000323303 |
5 | 3320111004002420413 |
6 | 45512253233314055 |
7 | 2646523413304301 |
oct | 314310255007363 |
9 | 54652270282008 |
10 | 14045662154483 |
11 | 4525806131143 |
12 | 16aa187a0592b |
13 | 7ab6670b347b |
14 | 367b56a23271 |
15 | 19555ea35608 |
hex | cc642b40ef3 |
14045662154483 has 2 divisors, whose sum is σ = 14045662154484. Its totient is φ = 14045662154482.
The previous prime is 14045662154477. The next prime is 14045662154533. The reversal of 14045662154483 is 38445126654041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14045662154483 - 210 = 14045662153459 is a prime.
It is not a weakly prime, because it can be changed into another prime (14045662154473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7022831077241 + 7022831077242.
It is an arithmetic number, because the mean of its divisors is an integer number (7022831077242).
Almost surely, 214045662154483 is an apocalyptic number.
14045662154483 is a deficient number, since it is larger than the sum of its proper divisors (1).
14045662154483 is an equidigital number, since it uses as much as digits as its factorization.
14045662154483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11059200, while the sum is 53.
The spelling of 14045662154483 in words is "fourteen trillion, forty-five billion, six hundred sixty-two million, one hundred fifty-four thousand, four hundred eighty-three".
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