Base | Representation |
---|---|
bin | 1100110001110101001000… |
… | …0010100000000001110001 |
3 | 1211202012001121012101220102 |
4 | 3030131102002200001301 |
5 | 3320144314342144101 |
6 | 45514325052122145 |
7 | 2650044260665256 |
oct | 314352202400161 |
9 | 54665047171812 |
10 | 14050214412401 |
11 | 4527731824972 |
12 | 16ab038466355 |
13 | 7abc11255ccb |
14 | 36806945342d |
15 | 1957294e786b |
hex | cc7520a0071 |
14050214412401 has 2 divisors, whose sum is σ = 14050214412402. Its totient is φ = 14050214412400.
The previous prime is 14050214412361. The next prime is 14050214412407. The reversal of 14050214412401 is 10421441205041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13486815553600 + 563398858801 = 3672440^2 + 750599^2 .
It is a cyclic number.
It is not a de Polignac number, because 14050214412401 - 26 = 14050214412337 is a prime.
It is not a weakly prime, because it can be changed into another prime (14050214412407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7025107206200 + 7025107206201.
It is an arithmetic number, because the mean of its divisors is an integer number (7025107206201).
Almost surely, 214050214412401 is an apocalyptic number.
It is an amenable number.
14050214412401 is a deficient number, since it is larger than the sum of its proper divisors (1).
14050214412401 is an equidigital number, since it uses as much as digits as its factorization.
14050214412401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5120, while the sum is 29.
Adding to 14050214412401 its reverse (10421441205041), we get a palindrome (24471655617442).
The spelling of 14050214412401 in words is "fourteen trillion, fifty billion, two hundred fourteen million, four hundred twelve thousand, four hundred one".
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