Base | Representation |
---|---|
bin | 11010001010111011… |
… | …10000111010111011 |
3 | 1100021012011211120112 |
4 | 31011131300322323 |
5 | 212233341113342 |
6 | 10242111214535 |
7 | 1005115566032 |
oct | 150535607273 |
9 | 40235154515 |
10 | 14050332347 |
11 | 5a60056717 |
12 | 288151744b |
13 | 142bb8262c |
14 | 974059719 |
15 | 573776682 |
hex | 345770ebb |
14050332347 has 2 divisors, whose sum is σ = 14050332348. Its totient is φ = 14050332346.
The previous prime is 14050332313. The next prime is 14050332377. The reversal of 14050332347 is 74323305041.
It is a strong prime.
It is an emirp because it is prime and its reverse (74323305041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14050332347 - 214 = 14050315963 is a prime.
It is a super-2 number, since 2×140503323472 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14050332377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7025166173 + 7025166174.
It is an arithmetic number, because the mean of its divisors is an integer number (7025166174).
Almost surely, 214050332347 is an apocalyptic number.
14050332347 is a deficient number, since it is larger than the sum of its proper divisors (1).
14050332347 is an equidigital number, since it uses as much as digits as its factorization.
14050332347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30240, while the sum is 32.
Adding to 14050332347 its reverse (74323305041), we get a palindrome (88373637388).
The spelling of 14050332347 in words is "fourteen billion, fifty million, three hundred thirty-two thousand, three hundred forty-seven".
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