Base | Representation |
---|---|
bin | 1100110001111100110011… |
… | …0110001110100011111001 |
3 | 1211202101101012011120022202 |
4 | 3030133030312032203321 |
5 | 3320213024321331242 |
6 | 45515305333155545 |
7 | 2650146316640021 |
oct | 314371466164371 |
9 | 54671335146282 |
10 | 14052274792697 |
11 | 45285998620a9 |
12 | 16ab51248bbb5 |
13 | 7ac17c08144b |
14 | 3681c2d48a81 |
15 | 1957ea335932 |
hex | cc7ccd8e8f9 |
14052274792697 has 2 divisors, whose sum is σ = 14052274792698. Its totient is φ = 14052274792696.
The previous prime is 14052274792631. The next prime is 14052274792709. The reversal of 14052274792697 is 79629747225041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13249738320361 + 802536472336 = 3640019^2 + 895844^2 .
It is a cyclic number.
It is not a de Polignac number, because 14052274792697 - 28 = 14052274792441 is a prime.
It is not a weakly prime, because it can be changed into another prime (14052274797697) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7026137396348 + 7026137396349.
It is an arithmetic number, because the mean of its divisors is an integer number (7026137396349).
Almost surely, 214052274792697 is an apocalyptic number.
It is an amenable number.
14052274792697 is a deficient number, since it is larger than the sum of its proper divisors (1).
14052274792697 is an equidigital number, since it uses as much as digits as its factorization.
14052274792697 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 106686720, while the sum is 65.
The spelling of 14052274792697 in words is "fourteen trillion, fifty-two billion, two hundred seventy-four million, seven hundred ninety-two thousand, six hundred ninety-seven".
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