Base | Representation |
---|---|
bin | 1100110001111101110101… |
… | …1000101001011101110011 |
3 | 1211202102002112020220220111 |
4 | 3030133131120221131303 |
5 | 3320214111334020001 |
6 | 45515353044122151 |
7 | 2650156226204053 |
oct | 314373530513563 |
9 | 54672075226814 |
10 | 14052552251251 |
11 | 452872143a898 |
12 | 16ab58b396357 |
13 | 7ac1c46b90c7 |
14 | 36820bb31563 |
15 | 195814890851 |
hex | cc7dd629773 |
14052552251251 has 8 divisors (see below), whose sum is σ = 14070617020208. Its totient is φ = 14034489300000.
The previous prime is 14052552251239. The next prime is 14052552251293. The reversal of 14052552251251 is 15215225525041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14052552251251 - 215 = 14052552218483 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14052552351251) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15371041 + ... + 16259581.
It is an arithmetic number, because the mean of its divisors is an integer number (1758827127526).
Almost surely, 214052552251251 is an apocalyptic number.
14052552251251 is a deficient number, since it is larger than the sum of its proper divisors (18064768957).
14052552251251 is an equidigital number, since it uses as much as digits as its factorization.
14052552251251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 908853.
The product of its (nonzero) digits is 200000, while the sum is 40.
Adding to 14052552251251 its reverse (15215225525041), we get a palindrome (29267777776292).
The spelling of 14052552251251 in words is "fourteen trillion, fifty-two billion, five hundred fifty-two million, two hundred fifty-one thousand, two hundred fifty-one".
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