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14052652270403 is a prime number
BaseRepresentation
bin1100110001111110001101…
…0110001100001101000011
31211202102100111110102101112
43030133203112030031003
53320214312440123103
645515411015553535
72650161552306065
oct314374326141503
954672314412345
1014052652270403
11452877294474a
1216ab5b898b8ab
137ac20c338536
1436821b129735
1519581d54acd8
hexcc7e358c343

14052652270403 has 2 divisors, whose sum is σ = 14052652270404. Its totient is φ = 14052652270402.

The previous prime is 14052652270387. The next prime is 14052652270427. The reversal of 14052652270403 is 30407225625041.

14052652270403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14052652270403 - 24 = 14052652270387 is a prime.

It is not a weakly prime, because it can be changed into another prime (14052652270493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7026326135201 + 7026326135202.

It is an arithmetic number, because the mean of its divisors is an integer number (7026326135202).

Almost surely, 214052652270403 is an apocalyptic number.

14052652270403 is a deficient number, since it is larger than the sum of its proper divisors (1).

14052652270403 is an equidigital number, since it uses as much as digits as its factorization.

14052652270403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 403200, while the sum is 41.

Adding to 14052652270403 its reverse (30407225625041), we get a palindrome (44459877895444).

The spelling of 14052652270403 in words is "fourteen trillion, fifty-two billion, six hundred fifty-two million, two hundred seventy thousand, four hundred three".