Base | Representation |
---|---|
bin | 1100110001111110001101… |
… | …0110001100001101000011 |
3 | 1211202102100111110102101112 |
4 | 3030133203112030031003 |
5 | 3320214312440123103 |
6 | 45515411015553535 |
7 | 2650161552306065 |
oct | 314374326141503 |
9 | 54672314412345 |
10 | 14052652270403 |
11 | 452877294474a |
12 | 16ab5b898b8ab |
13 | 7ac20c338536 |
14 | 36821b129735 |
15 | 19581d54acd8 |
hex | cc7e358c343 |
14052652270403 has 2 divisors, whose sum is σ = 14052652270404. Its totient is φ = 14052652270402.
The previous prime is 14052652270387. The next prime is 14052652270427. The reversal of 14052652270403 is 30407225625041.
14052652270403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14052652270403 - 24 = 14052652270387 is a prime.
It is not a weakly prime, because it can be changed into another prime (14052652270493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7026326135201 + 7026326135202.
It is an arithmetic number, because the mean of its divisors is an integer number (7026326135202).
Almost surely, 214052652270403 is an apocalyptic number.
14052652270403 is a deficient number, since it is larger than the sum of its proper divisors (1).
14052652270403 is an equidigital number, since it uses as much as digits as its factorization.
14052652270403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 403200, while the sum is 41.
Adding to 14052652270403 its reverse (30407225625041), we get a palindrome (44459877895444).
The spelling of 14052652270403 in words is "fourteen trillion, fifty-two billion, six hundred fifty-two million, two hundred seventy thousand, four hundred three".
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