Base | Representation |
---|---|
bin | 1100110001111111111000… |
… | …0011101110001010100011 |
3 | 1211202110111201201110021211 |
4 | 3030133332003232022203 |
5 | 3320221222201213403 |
6 | 45515523305130551 |
7 | 2650205633413036 |
oct | 314377603561243 |
9 | 54673451643254 |
10 | 14053100413603 |
11 | 4528982902329 |
12 | 16ab702a89a57 |
13 | 7ac281135024 |
14 | 36826086301d |
15 | 195847a6e06d |
hex | cc7fe0ee2a3 |
14053100413603 has 2 divisors, whose sum is σ = 14053100413604. Its totient is φ = 14053100413602.
The previous prime is 14053100413543. The next prime is 14053100413717. The reversal of 14053100413603 is 30631400135041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14053100413603 - 213 = 14053100405411 is a prime.
It is not a weakly prime, because it can be changed into another prime (14053100410603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7026550206801 + 7026550206802.
It is an arithmetic number, because the mean of its divisors is an integer number (7026550206802).
Almost surely, 214053100413603 is an apocalyptic number.
14053100413603 is a deficient number, since it is larger than the sum of its proper divisors (1).
14053100413603 is an equidigital number, since it uses as much as digits as its factorization.
14053100413603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 14053100413603 its reverse (30631400135041), we get a palindrome (44684500548644).
The spelling of 14053100413603 in words is "fourteen trillion, fifty-three billion, one hundred million, four hundred thirteen thousand, six hundred three".
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