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14053113541203 = 3111093906898399
BaseRepresentation
bin1100110001111111111011…
…0101110011001001010011
31211202110112122102101222020
43030133332311303021103
53320221234031304303
645515524454342523
72650206153116652
oct314377665631123
954673478371866
1014053113541203
11452898a259290
1216ab70735aa43
137ac283a80339
143682624bd199
15195848cb3a53
hexcc7fed73253

14053113541203 has 16 divisors (see below), whose sum is σ = 20628423552000. Its totient is φ = 8438900539680.

The previous prime is 14053113541193. The next prime is 14053113541211. The reversal of 14053113541203 is 30214531135041.

It is not a de Polignac number, because 14053113541203 - 217 = 14053113410131 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (33).

It is not an unprimeable number, because it can be changed into a prime (14053113541283) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1953445603 + ... + 1953452796.

It is an arithmetic number, because the mean of its divisors is an integer number (1289276472000).

Almost surely, 214053113541203 is an apocalyptic number.

14053113541203 is a deficient number, since it is larger than the sum of its proper divisors (6575310010797).

14053113541203 is a wasteful number, since it uses less digits than its factorization.

14053113541203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3906898522.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 14053113541203 its reverse (30214531135041), we get a palindrome (44267644676244).

The spelling of 14053113541203 in words is "fourteen trillion, fifty-three billion, one hundred thirteen million, five hundred forty-one thousand, two hundred three".

Divisors: 1 3 11 33 109 327 1199 3597 3906898399 11720695197 42975882389 128927647167 425851925491 1277555776473 4684371180401 14053113541203