Base | Representation |
---|---|
bin | 11010001011010001… |
… | …00100011100100001 |
3 | 1100021101111202000102 |
4 | 31011220210130201 |
5 | 212240102233313 |
6 | 10242252032145 |
7 | 1005151634021 |
oct | 150550443441 |
9 | 40241452012 |
10 | 14053164833 |
11 | 5a61710814 |
12 | 2882462655 |
13 | 142c634966 |
14 | 974595a81 |
15 | 573b35a58 |
hex | 345a24721 |
14053164833 has 2 divisors, whose sum is σ = 14053164834. Its totient is φ = 14053164832.
The previous prime is 14053164817. The next prime is 14053164901. The reversal of 14053164833 is 33846135041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12057577249 + 1995587584 = 109807^2 + 44672^2 .
It is an emirp because it is prime and its reverse (33846135041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14053164833 - 24 = 14053164817 is a prime.
It is not a weakly prime, because it can be changed into another prime (14053161833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7026582416 + 7026582417.
It is an arithmetic number, because the mean of its divisors is an integer number (7026582417).
Almost surely, 214053164833 is an apocalyptic number.
It is an amenable number.
14053164833 is a deficient number, since it is larger than the sum of its proper divisors (1).
14053164833 is an equidigital number, since it uses as much as digits as its factorization.
14053164833 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 38.
Adding to 14053164833 its reverse (33846135041), we get a palindrome (47899299874).
The spelling of 14053164833 in words is "fourteen billion, fifty-three million, one hundred sixty-four thousand, eight hundred thirty-three".
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