14055552115441 has 2 divisors, whose sum is σ = 14055552115442. Its totient is φ = 14055552115440.

The previous prime is 14055552115399. The next prime is 14055552115459. The reversal of 14055552115441 is 14451125555041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8610679884816 + 5444872230625 = 2934396^2 + 2333425^2 .

It is a cyclic number.

It is not a de Polignac number, because 14055552115441 - 2¹³ = 14055552107249 is a prime.

It is a super-3 number, since 3×14055552115441³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (14055552115541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7027776057720 + 7027776057721.

It is an arithmetic number, because the mean of its divisors is an integer number (7027776057721).

Almost surely, 2^{14055552115441} is an apocalyptic number.

It is an amenable number.

14055552115441 is a deficient number, since it is larger than the sum of its proper divisors (1).

14055552115441 is an equidigital number, since it uses as much as digits as its factorization.

14055552115441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 400000, while the sum is 43.

The spelling of 14055552115441 in words is "fourteen trillion, fifty-five billion, five hundred fifty-two million, one hundred fifteen thousand, four hundred forty-one".