Base | Representation |
---|---|
bin | 1000001011111011100… |
… | …1100011100101100011 |
3 | 111110000120012020210012 |
4 | 2002332321203211203 |
5 | 4301013234244413 |
6 | 144335423555135 |
7 | 13106142555116 |
oct | 2027671434543 |
9 | 443016166705 |
10 | 140641712483 |
11 | 54711642238 |
12 | 2331075baab |
13 | 10354803a1c |
14 | 6b4295257d |
15 | 39d222d7a8 |
hex | 20bee63963 |
140641712483 has 2 divisors, whose sum is σ = 140641712484. Its totient is φ = 140641712482.
The previous prime is 140641712401. The next prime is 140641712689. The reversal of 140641712483 is 384217146041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140641712483 - 212 = 140641708387 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 140641712483.
It is not a weakly prime, because it can be changed into another prime (140641712083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70320856241 + 70320856242.
It is an arithmetic number, because the mean of its divisors is an integer number (70320856242).
Almost surely, 2140641712483 is an apocalyptic number.
140641712483 is a deficient number, since it is larger than the sum of its proper divisors (1).
140641712483 is an equidigital number, since it uses as much as digits as its factorization.
140641712483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129024, while the sum is 41.
The spelling of 140641712483 in words is "one hundred forty billion, six hundred forty-one million, seven hundred twelve thousand, four hundred eighty-three".
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