Base | Representation |
---|---|
bin | 11111111111001011100001… |
… | …011100010100101010011011 |
3 | 200110002222121121102010201110 |
4 | 133333023201130110222123 |
5 | 121414404434111031301 |
6 | 1215112005104551403 |
7 | 41426606552146203 |
oct | 3777134134245233 |
9 | 613088547363643 |
10 | 140681141111451 |
11 | 4090959a675836 |
12 | 13940b45622563 |
13 | 6066236a19095 |
14 | 26a5009aab403 |
15 | 113e68cad00d6 |
hex | 7ff2e1714a9b |
140681141111451 has 4 divisors (see below), whose sum is σ = 187574854815272. Its totient is φ = 93787427407632.
The previous prime is 140681141111443. The next prime is 140681141111473. The reversal of 140681141111451 is 154111141186041.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 140681141111451 - 23 = 140681141111443 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (140681141111051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23446856851906 + ... + 23446856851911.
It is an arithmetic number, because the mean of its divisors is an integer number (46893713703818).
Almost surely, 2140681141111451 is an apocalyptic number.
140681141111451 is a deficient number, since it is larger than the sum of its proper divisors (46893713703821).
140681141111451 is an equidigital number, since it uses as much as digits as its factorization.
140681141111451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46893713703820.
The product of its (nonzero) digits is 15360, while the sum is 39.
Adding to 140681141111451 its reverse (154111141186041), we get a palindrome (294792282297492).
The spelling of 140681141111451 in words is "one hundred forty trillion, six hundred eighty-one billion, one hundred forty-one million, one hundred eleven thousand, four hundred fifty-one".
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