1408111341347 has 4 divisors (see below), whose sum is σ = 1418860283016. Its totient is φ = 1397362399680.

The previous prime is 1408111341311. The next prime is 1408111341431. The reversal of 1408111341347 is 7431431118041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1408111341347 - 2³⁴ = 1390931472163 is a prime.

It is a super-3 number, since 3×1408111341347³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1408111341347.

It is not an unprimeable number, because it can be changed into a prime (1408111341547) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5374470638 + ... + 5374470899.

It is an arithmetic number, because the mean of its divisors is an integer number (354715070754).

Almost surely, 2^{1408111341347} is an apocalyptic number.

1408111341347 is a deficient number, since it is larger than the sum of its proper divisors (10748941669).

1408111341347 is a wasteful number, since it uses less digits than its factorization.

1408111341347 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10748941668.

The product of its (nonzero) digits is 32256, while the sum is 38.

Adding to 1408111341347 its reverse (7431431118041), we get a palindrome (8839542459388).

The spelling of 1408111341347 in words is "one trillion, four hundred eight billion, one hundred eleven million, three hundred forty-one thousand, three hundred forty-seven".