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14081275656131 is a prime number
BaseRepresentation
bin1100110011101000110101…
…1011101111011111000011
31211212011020022102001222212
43030322031123233133003
53321201423031444011
645540503154252335
72652224065132205
oct314721533573703
954764208361885
1014081275656131
114539921012032
1216b50668870ab
137b1b2144c378
143697747cc775
1519644639e08b
hexcce8d6ef7c3

14081275656131 has 2 divisors, whose sum is σ = 14081275656132. Its totient is φ = 14081275656130.

The previous prime is 14081275656059. The next prime is 14081275656137. The reversal of 14081275656131 is 13165657218041.

It is a strong prime.

It is an emirp because it is prime and its reverse (13165657218041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14081275656131 - 242 = 9683229145027 is a prime.

It is a super-2 number, since 2×140812756561312 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14081275656131.

It is not a weakly prime, because it can be changed into another prime (14081275656137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7040637828065 + 7040637828066.

It is an arithmetic number, because the mean of its divisors is an integer number (7040637828066).

Almost surely, 214081275656131 is an apocalyptic number.

14081275656131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14081275656131 is an equidigital number, since it uses as much as digits as its factorization.

14081275656131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1209600, while the sum is 50.

The spelling of 14081275656131 in words is "fourteen trillion, eighty-one billion, two hundred seventy-five million, six hundred fifty-six thousand, one hundred thirty-one".