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14082257356273 is a prime number
BaseRepresentation
bin1100110011101100011111…
…1100101000010111110001
31211212020202201122121102101
43030323013330220113301
53321210430340400043
645541144423420401
72652260315344561
oct314730774502761
954766681577371
1014082257356273
11453a285176967
1216b529b5b4701
137b1c4994cc22
14369828d34da1
151964a266824d
hexccec7f285f1

14082257356273 has 2 divisors, whose sum is σ = 14082257356274. Its totient is φ = 14082257356272.

The previous prime is 14082257356087. The next prime is 14082257356331. The reversal of 14082257356273 is 37265375228041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12610225983744 + 1472031372529 = 3551088^2 + 1213273^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14082257356273 is a prime.

It is not a weakly prime, because it can be changed into another prime (14082257354273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7041128678136 + 7041128678137.

It is an arithmetic number, because the mean of its divisors is an integer number (7041128678137).

Almost surely, 214082257356273 is an apocalyptic number.

It is an amenable number.

14082257356273 is a deficient number, since it is larger than the sum of its proper divisors (1).

14082257356273 is an equidigital number, since it uses as much as digits as its factorization.

14082257356273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16934400, while the sum is 55.

The spelling of 14082257356273 in words is "fourteen trillion, eighty-two billion, two hundred fifty-seven million, three hundred fifty-six thousand, two hundred seventy-three".