Base | Representation |
---|---|
bin | 100000000011110100100110… |
… | …101111101110000101011011 |
3 | 200111020110222120220222122121 |
4 | 200003310212233232011123 |
5 | 121440121232114412443 |
6 | 1215514322142002111 |
7 | 41461631461664365 |
oct | 4003644657560533 |
9 | 614213876828577 |
10 | 141000131404123 |
11 | 40a21902347a92 |
12 | 1399292a876337 |
13 | 608a341c96b54 |
14 | 26b662ad7bd35 |
15 | 1147b0c55c4ed |
hex | 803d26bee15b |
141000131404123 has 2 divisors, whose sum is σ = 141000131404124. Its totient is φ = 141000131404122.
The previous prime is 141000131404063. The next prime is 141000131404133. The reversal of 141000131404123 is 321404131000141.
141000131404123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141000131404123 is a prime.
It is not a weakly prime, because it can be changed into another prime (141000131404133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70500065702061 + 70500065702062.
It is an arithmetic number, because the mean of its divisors is an integer number (70500065702062).
Almost surely, 2141000131404123 is an apocalyptic number.
141000131404123 is a deficient number, since it is larger than the sum of its proper divisors (1).
141000131404123 is an equidigital number, since it uses as much as digits as its factorization.
141000131404123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 141000131404123 its reverse (321404131000141), we get a palindrome (462404262404264).
The spelling of 141000131404123 in words is "one hundred forty-one trillion, one hundred thirty-one million, four hundred four thousand, one hundred twenty-three".
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