Base | Representation |
---|---|
bin | 10100100001001011001… |
… | …101010001011001110010 |
3 | 11222210111002112111100121 |
4 | 110201023031101121302 |
5 | 141100200311342232 |
6 | 2555430010040454 |
7 | 203604250055431 |
oct | 24411315213162 |
9 | 4883432474317 |
10 | 1410011043442 |
11 | 4a3a89525411 |
12 | 1a9329a1912a |
13 | a2c6a98cb11 |
14 | 4c360005118 |
15 | 26a26e9ed97 |
hex | 1484b351672 |
1410011043442 has 4 divisors (see below), whose sum is σ = 2115016565166. Its totient is φ = 705005521720.
The previous prime is 1410011043439. The next prime is 1410011043491. The reversal of 1410011043442 is 2443401100141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1348596786681 + 61414256761 = 1161291^2 + 247819^2 .
It is a super-2 number, since 2×14100110434422 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 352502760859 + ... + 352502760862.
Almost surely, 21410011043442 is an apocalyptic number.
1410011043442 is a deficient number, since it is larger than the sum of its proper divisors (705005521724).
1410011043442 is an equidigital number, since it uses as much as digits as its factorization.
1410011043442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 705005521723.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1410011043442 its reverse (2443401100141), we get a palindrome (3853412143583).
The spelling of 1410011043442 in words is "one trillion, four hundred ten billion, eleven million, forty-three thousand, four hundred forty-two".
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