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141001200310057 is a prime number
BaseRepresentation
bin100000000011110101100110…
…011101010001011100101001
3200111020120202002021000221021
4200003311212131101130221
5121440130424234410212
61215515020204212441
741462000121354253
oct4003654635213451
9614216662230837
10141001200310057
1140a2230075491a
1213992b8883a121
13608a48257b879
1426b66ccd04cd3
151147b71300307
hex803d66751729

141001200310057 has 2 divisors, whose sum is σ = 141001200310058. Its totient is φ = 141001200310056.

The previous prime is 141001200309973. The next prime is 141001200310171. The reversal of 141001200310057 is 750013002100141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111961560653721 + 29039639656336 = 10581189^2 + 5388844^2 .

It is a cyclic number.

It is not a de Polignac number, because 141001200310057 - 27 = 141001200309929 is a prime.

It is not a weakly prime, because it can be changed into another prime (141001200310757) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70500600155028 + 70500600155029.

It is an arithmetic number, because the mean of its divisors is an integer number (70500600155029).

Almost surely, 2141001200310057 is an apocalyptic number.

It is an amenable number.

141001200310057 is a deficient number, since it is larger than the sum of its proper divisors (1).

141001200310057 is an equidigital number, since it uses as much as digits as its factorization.

141001200310057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 840, while the sum is 25.

Adding to 141001200310057 its reverse (750013002100141), we get a palindrome (891014202410198).

The spelling of 141001200310057 in words is "one hundred forty-one trillion, one billion, two hundred million, three hundred ten thousand, fifty-seven".