Base | Representation |
---|---|
bin | 100000000011110101100110… |
… | …011101010001011100101001 |
3 | 200111020120202002021000221021 |
4 | 200003311212131101130221 |
5 | 121440130424234410212 |
6 | 1215515020204212441 |
7 | 41462000121354253 |
oct | 4003654635213451 |
9 | 614216662230837 |
10 | 141001200310057 |
11 | 40a2230075491a |
12 | 13992b8883a121 |
13 | 608a48257b879 |
14 | 26b66ccd04cd3 |
15 | 1147b71300307 |
hex | 803d66751729 |
141001200310057 has 2 divisors, whose sum is σ = 141001200310058. Its totient is φ = 141001200310056.
The previous prime is 141001200309973. The next prime is 141001200310171. The reversal of 141001200310057 is 750013002100141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111961560653721 + 29039639656336 = 10581189^2 + 5388844^2 .
It is a cyclic number.
It is not a de Polignac number, because 141001200310057 - 27 = 141001200309929 is a prime.
It is not a weakly prime, because it can be changed into another prime (141001200310757) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70500600155028 + 70500600155029.
It is an arithmetic number, because the mean of its divisors is an integer number (70500600155029).
Almost surely, 2141001200310057 is an apocalyptic number.
It is an amenable number.
141001200310057 is a deficient number, since it is larger than the sum of its proper divisors (1).
141001200310057 is an equidigital number, since it uses as much as digits as its factorization.
141001200310057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 840, while the sum is 25.
Adding to 141001200310057 its reverse (750013002100141), we get a palindrome (891014202410198).
The spelling of 141001200310057 in words is "one hundred forty-one trillion, one billion, two hundred million, three hundred ten thousand, fifty-seven".
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